(2m-5)(m+4)=k+2m^2

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Solution for (2m-5)(m+4)=k+2m^2 equation:


Simplifying
(2m + -5)(m + 4) = k + 2m2

Reorder the terms:
(-5 + 2m)(m + 4) = k + 2m2

Reorder the terms:
(-5 + 2m)(4 + m) = k + 2m2

Multiply (-5 + 2m) * (4 + m)
(-5(4 + m) + 2m * (4 + m)) = k + 2m2
((4 * -5 + m * -5) + 2m * (4 + m)) = k + 2m2
((-20 + -5m) + 2m * (4 + m)) = k + 2m2
(-20 + -5m + (4 * 2m + m * 2m)) = k + 2m2
(-20 + -5m + (8m + 2m2)) = k + 2m2

Combine like terms: -5m + 8m = 3m
(-20 + 3m + 2m2) = k + 2m2

Add '-2m2' to each side of the equation.
-20 + 3m + 2m2 + -2m2 = k + 2m2 + -2m2

Combine like terms: 2m2 + -2m2 = 0
-20 + 3m + 0 = k + 2m2 + -2m2
-20 + 3m = k + 2m2 + -2m2

Combine like terms: 2m2 + -2m2 = 0
-20 + 3m = k + 0
-20 + 3m = k

Solving
-20 + 3m = k

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 20 + 3m = 20 + k

Combine like terms: -20 + 20 = 0
0 + 3m = 20 + k
3m = 20 + k

Divide each side by '3'.
m = 6.666666667 + 0.3333333333k

Simplifying
m = 6.666666667 + 0.3333333333k

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